LeetCode Python/Java/C++/JS > 28. Find the Index of the First Occurrence in a String > Solved in Python, JavaScript, Ruby, C++, Java, Go, C# > GitHub
LeetCode link: 28. Find the Index of the First Occurrence in a String, difficulty: Easy.
Given two strings needle and haystack, return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Example 1:
Input: haystack = "sadbutsad", needle = "sad"
Output: 0
Explanation:
"sad" occurs at index 0 and 6.
The first occurrence is at index 0, so we return 0.
Example 2:
Input: haystack = "leetcode", needle = "leeto"
Output: -1
Explanation:
"leeto" did not occur in "leetcode", so we return -1.
Constraints:
1 <= haystack.length, needle.length <= 10000haystackandneedleconsist of only lowercase English characters.
Topics
Intuition
This kind of question can be solved with one line of code using the built-in
index(). Obviously, the questioner wants to test our ability to control the loop.For
heystack, iterate through each character in turn. If the substring from the current character toneedleis the same asneedle, return the position of the current character.This question is easier to understand by looking at the code directly.
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Complexity
Time complexity
O(N * M)
Space complexity
O(1)
Python #
class Solution:
def strStr(self, haystack: str, needle: str) -> int:
n = len(haystack)
m = len(needle)
for i in range(n - m + 1):
if haystack[i:i + m] == needle:
return i
return -1
JavaScript #
/**
* @param {string} haystack
* @param {string} needle
* @return {number}
*/
var strStr = function(haystack, needle) {
const n = haystack.length;
const m = needle.length;
for (let i = 0; i <= n - m; i++) {
if (haystack.substring(i, i + m) === needle) {
return i;
}
}
return -1;
};
Ruby #
# @param {String} haystack
# @param {String} needle
# @return {Integer}
def str_str(haystack, needle)
(0..haystack.size - needle.size).each do |i|
if haystack[i...i + needle.size] == needle
return i
end
end
-1
end
C++ #
class Solution {
public:
int strStr(string haystack, string needle) {
for (int i = 0; i < haystack.length(); i++) {
int j = 0;
while (i + j < haystack.length() && haystack[i + j] == needle[j]) {
j++;
if (j == needle.length()) {
return i;
}
}
}
return -1;
}
};
Java #
class Solution {
public int strStr(String haystack, String needle) {
for (int i = 0; i < haystack.length(); i++) {
int j = 0;
while (i + j < haystack.length() && haystack.charAt(i + j) == needle.charAt(j)) {
j++;
if (j == needle.length()) {
return i;
}
}
}
return -1;
}
}
Go #
func strStr(haystack string, needle string) int {
for i := 0; i < len(haystack); i++ {
j := 0
for i+j < len(haystack) && haystack[i+j] == needle[j] {
j++
if j == len(needle) {
return i
}
}
}
return -1
}
C# #
public class Solution {
public int StrStr(string haystack, string needle) {
for (int i = 0; i < haystack.Length; i++) {
int j = 0;
while (i + j < haystack.Length && haystack[i + j] == needle[j]) {
j++;
if (j == needle.Length) {
return i;
}
}
}
return -1;
}
}
Other languages
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